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-.0125x^2+0.5x+1.5=0
We add all the numbers together, and all the variables
-0.0125x^2+0.5x+1.5=0
a = -0.0125; b = 0.5; c = +1.5;
Δ = b2-4ac
Δ = 0.52-4·(-0.0125)·1.5
Δ = 0.325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{0.325}}{2*-0.0125}=\frac{-0.5-\sqrt{0.325}}{-0.025} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{0.325}}{2*-0.0125}=\frac{-0.5+\sqrt{0.325}}{-0.025} $
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